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	<title>Comments on: Combinations and Permutations Episode 31: S/T</title>
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		<title>By: Combinations and Permutations Episode 52:Let&#8217;s Just Insult Sam &#171; ACME Science</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-825</link>
		<dc:creator>Combinations and Permutations Episode 52:Let&#8217;s Just Insult Sam &#171; ACME Science</dc:creator>
		<pubDate>Tue, 21 Sep 2010 16:47:15 +0000</pubDate>
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		<description>[...] Combinatorics Podcast [...]</description>
		<content:encoded><![CDATA[<p>[...] Combinatorics Podcast [...]</p>
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		<title>By: samuel</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-128</link>
		<dc:creator>samuel</dc:creator>
		<pubDate>Sun, 06 Dec 2009 23:47:07 +0000</pubDate>
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		<description>Well I hope the best for you on the job front, it is hard out there I hear(I have to have heard it because I am so woefully underpaid that my university is not about to let me go).</description>
		<content:encoded><![CDATA[<p>Well I hope the best for you on the job front, it is hard out there I hear(I have to have heard it because I am so woefully underpaid that my university is not about to let me go).</p>
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		<title>By: J. Bowman</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-126</link>
		<dc:creator>J. Bowman</dc:creator>
		<pubDate>Sat, 05 Dec 2009 16:49:42 +0000</pubDate>
		<guid isPermaLink="false">http://acmescience.com/?p=241#comment-126</guid>
		<description>I forget who said it. It was a tangent.
The job search has entered Year Two - Year One ended with an adjunct offer, which was a nice change from &quot;sorry, it&#039;s just not the right fit.&quot; I&#039;m a little hampered by geographical concerns, but I&#039;m hopeful that the improved economy leads to more hiring - the campus down the street might have several openings.</description>
		<content:encoded><![CDATA[<p>I forget who said it. It was a tangent.<br />
The job search has entered Year Two &#8211; Year One ended with an adjunct offer, which was a nice change from &#8220;sorry, it&#8217;s just not the right fit.&#8221; I&#8217;m a little hampered by geographical concerns, but I&#8217;m hopeful that the improved economy leads to more hiring &#8211; the campus down the street might have several openings.</p>
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		<title>By: samuel</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-55</link>
		<dc:creator>samuel</dc:creator>
		<pubDate>Wed, 02 Dec 2009 01:26:18 +0000</pubDate>
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		<description>Well whoever said that needs to really polish up on their abstract obviously, I am rather sure it was not I as that seems much more mathematical than I am comfortable in being.

Otherwise, how have you been? The job search going well?</description>
		<content:encoded><![CDATA[<p>Well whoever said that needs to really polish up on their abstract obviously, I am rather sure it was not I as that seems much more mathematical than I am comfortable in being.</p>
<p>Otherwise, how have you been? The job search going well?</p>
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		<title>By: J. Bowman</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-53</link>
		<dc:creator>J. Bowman</dc:creator>
		<pubDate>Tue, 01 Dec 2009 20:10:30 +0000</pubDate>
		<guid isPermaLink="false">http://acmescience.com/?p=241#comment-53</guid>
		<description>Showing a group of 42 elements is not simple follows directly from Sylow Theorems:
a. There must be a subgroup of order 7.
b. The number of subgroups of order 7 must be congruent to 1 (mod 7), and must divide 42. Thus, there must be exactly one subgroup of order 7.
c. Because there is exactly one such subgroup, it must be normal. Therefore, the group is not simple.

Showing a group of order 72 is not simple, on the other hand, is quite a bit harder. Showing a group of order 90 is not simple is a bear.</description>
		<content:encoded><![CDATA[<p>Showing a group of 42 elements is not simple follows directly from Sylow Theorems:<br />
a. There must be a subgroup of order 7.<br />
b. The number of subgroups of order 7 must be congruent to 1 (mod 7), and must divide 42. Thus, there must be exactly one subgroup of order 7.<br />
c. Because there is exactly one such subgroup, it must be normal. Therefore, the group is not simple.</p>
<p>Showing a group of order 72 is not simple, on the other hand, is quite a bit harder. Showing a group of order 90 is not simple is a bear.</p>
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		<title>By: samuel</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-47</link>
		<dc:creator>samuel</dc:creator>
		<pubDate>Sun, 29 Nov 2009 06:52:27 +0000</pubDate>
		<guid isPermaLink="false">http://acmescience.com/?p=241#comment-47</guid>
		<description>I must have forgotten completely what we talked about in this episode, as I have no memories of prank calls. I need to pay more attention to the show I host apparently.</description>
		<content:encoded><![CDATA[<p>I must have forgotten completely what we talked about in this episode, as I have no memories of prank calls. I need to pay more attention to the show I host apparently.</p>
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		<title>By: Henrik</title>
		<link>http://acmescience.com/shows/cp-shows/241/comment-page-1#comment-38</link>
		<dc:creator>Henrik</dc:creator>
		<pubDate>Thu, 26 Nov 2009 18:43:06 +0000</pubDate>
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		<description>I&#039;m all for prank calls, but doing it from 9 timezones away is just a little bit too creepy for my tastes.</description>
		<content:encoded><![CDATA[<p>I&#8217;m all for prank calls, but doing it from 9 timezones away is just a little bit too creepy for my tastes.</p>
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